I hear they are also going to be releasing another product 'HeatSave' soon which are Wireless TRV's that replace your existing radiator valve and allow wireless control. I'll be getting a couple to see how good they are when they're released
The answer on your question depends on both the specific model of the device you want to describe and the testing conditions. Especially your definition of 'useful output'.
Since I've been recenty looking around for a fridge/freezer, I can tell you that a reasonably sized standing model in efficiency class A+++ (best you can get at the moment) will use 170 kWh/year under normalized testing conditions. 170 kWh = 170 * 1000 * 3600 Joules = 612 MJ.
Total input energy vs. useful output is a ratio and that simply equals efficiency of an appliance. Are you meaning a specific brand/model? An automatic energy loss is the heat radiated from both during its internal cooling process.
not sure
That is hard to answer the way that you have explained it. To figure input energy you need to know the voltage and amperage of the device. That multiplied equals wattage. That is the amount of energy that it uses. Then you need to know the BTU rating of the device to see the relationship between the thermal efficiency in generation by wattage of the device, example is watts per btu.
I can tell you that most of the waste is due to motor heat from the fan and compressor.
can you tell me:
total input energy
useful output
what the wasted energy comes out and how much from each.
for a fridge, freezer and fridgfreezer.
I need to write a report on them so I need as much info as possible, but it needs to be easy to understand.
thankyou (: x
